Page Title

On Your Marks...!!!!!!

Sara Will Rise Above!

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Let's Get Even!!!

Our client has asked us to find out how far of a head start Chad needs to intersect with us, but we will still win

snide steve vs. our client

GO SARA!

According to our research and calculations, we have gathered that we will need to give Cheat'n Chad a 4 meter headstart to win against Sara, our client.

how it will be even

Chad vs. Sara

Slope of Our Client, Sara: m= approx. 5.22 meters per second (1)

Slope of Chad: m=approx.4.5 meters per second (2)

SIF of Sara: y=5.22x+0

SIF of Chad: y=4.5x+4

(2)-(1)

0-72x-4=0

x = 5.56

WHEN x EQUALS 5.56

y= (5.22)(5.56)

y= 29.02

Meeting Point (intercept): (5.56, 29.02)

At 50 meters

x= 50/5.22 =approx. 9.58 (9.58, 50)

If we give Chad a 4 meter headstart

y= 5.22x (1)

y= 4.5x+8 (2)

(2)-(1)

0-72-8=0

x= 11.11

WHEN x EQUALS 11.11

y= (5.22)(11.11)

y= 58 meters

New Intercept (meeting point)

(11.11, 58)

YAY SARA!!!!

Our Client was also curious as to what the number had to be for herself to match up with Snide Steve

After Precisely calculating the relationships between Sara's data and Snide Steve's, we detirmed that a 3 second headstart was in order.

Steve vs. Sara

Slope of Our client, Sara: 5.22

Slope of Steve: 10

SIF: (Sara) y=5.22x-0

SIF: (Steve) y=10x-20

Steve-Sara

4.68x-20=0

x= 4.18

WHEN x EQUALS 4.18

y= (5.22)(4.18)

=21.28

Intercepting Point: (4.18, 21.82)

If we give Steve an additional 3 second headstart

Steve’s new starting point, (5,0)

y= mx+b

0=(10)(5)+b

b=-50

New SIF for Steve-------y= 10x-50

Sara-Steve

4.78x-50=0

x= 10.46

WHEN x EQUALS 10.46

y=(5.22)(10.46)

= 54.60

New Intercepting Point (10.46, 54.60)

Emily Todd, Sara Chin, Arturo Rojas, Shea Calvin